Answer:
Option D 12 is the answer.
Step-by-step explanation:
Given is a quadratic equation as
[tex]x^2-13x+12=0[/tex]
To find the roots we can factorise this
Since last term = 12, and middle term -13 we can split middle term as -12 and -1
[tex]x^2-12x-x+12 =0\\x(x-12)-1(x-12)=0\\(x-12)(x-1)=0\\x=12: x=1[/tex]
We know that there are two roots as 12 and 1.
The bigger root is obviously 12.
Option D is the answer
Verify:
Substitute 12 in the equation and check
[tex]12^2-13(12)+12=144-156+12=0[/tex]
Hence our answer is right.
