Respuesta :
interest is compounded quarterly. SOLUTION. i think i relly just looked it up srry if it isn't right
This can be solved with the equation
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
where A is the new/resulting balance
insert your interest r=0.0146
the starting amount P=9000
the number of times it gets compounded per year n=365 (every day)
and the number of years t=3
insert everything and calculate the balance in 3 years:
[tex]A=9000(1+\frac{0.0146}{365} )^{365*3} \\ =9000(1.00004)^{365*3} \\ =9000*1.0447...\\ =9402.95[/tex]
the amount earned over 3 years is then the new balance- the current balance:
9402.95-9000=402.95$ earned over 3 years
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
where A is the new/resulting balance
insert your interest r=0.0146
the starting amount P=9000
the number of times it gets compounded per year n=365 (every day)
and the number of years t=3
insert everything and calculate the balance in 3 years:
[tex]A=9000(1+\frac{0.0146}{365} )^{365*3} \\ =9000(1.00004)^{365*3} \\ =9000*1.0447...\\ =9402.95[/tex]
the amount earned over 3 years is then the new balance- the current balance:
9402.95-9000=402.95$ earned over 3 years