The volume of ice changes by 1/12
Explanation
Lets assume the volume of the water is V
When water freezes, its volume increases by 1/11 . So, the new volume of the ice[tex] = V+ \frac{V}{11}= \frac{11V+V}{11} = \frac{12V}{11} [/tex]
When the ice is melting, it returns to its original volume V. So, the volume decreased while melting[tex] = \frac{12V}{11}- V = \frac{V}{11} [/tex]
This time the volume has decreased [tex] \frac{V}{11} [/tex] from a starting point of [tex] \frac{12V}{11} [/tex]
So, the fraction of change will be : [tex] \frac{\frac{V}{11}}{\frac{12V}{11}} = \frac{V}{12V}= \frac{1}{12} [/tex]
