N2 (g) + 3H2 (g) -->2 NH3 (g) The equation above is the equation for the Haber process. In a certain reaction, you start with 6.0 moles of nitrogen and 10.0 moles of hydrogen. How many moles of ammonia will be produced in the reaction?
For ever 1 mole of nitrogen you need 3 moles of hydrogen to make 2 moles of Ammonia. We only have 10 moles of hydrogen so that is the limiting as there is more nitrogen then hydrogen in this particular case. Therfore the ratio is 2 ammonia to 3 hydrogen [2:3] Do 2/3which is 0.6667. This is how many moles of ammonia you get per mole of hydrogen. Multiply that by 10 and you get 6.67 moles of Ammonia produced [3 significant figures]
