Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width. Complete the equation that can be used to determine the dimensions of the monitor in terms of its width, w. = w2 - w
Draw the picture and label the width = w The length of the monitor is six times the quantity of five less than half its width: length = 6(w/2-5) length = 3w-30 Area = (length)*(width) 384=(3w-30)*(w) 384=3w^2-30w Answer: the dimensions of the monitor in terms of its width is: 384=3w^2-30w
