bruce has a pet worm that fell into a well. the well is 37 feet deep. each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet. how many days will it take for bruce’s worm to get to the top of the well

Respuesta :

7.4 days because it rises 5 each day and 37/5 is 7.4

Bruce's worm will take total 7.4 days to get to the top of the well.

What is sequence?

A sequence is an ordered list of numbers that often follow a specific pattern or function.

According to the given question.

Each day worm climbs up 7 feet, but each night it slides back down 2 feet.

Total number of feet the worm have to climb is 37.

On day one the worm climbs 7feet and slides slides 2 feet.

Therefore,

Total number of feet the worm climbs on day1 = 7 -2 = 5 feet

Similarly,

For day two, total number of feet worms climb on day2 = (5+7)-2 =10feet

Total number of feet worms climb on day on day 3 = (10 + 7) - 2 = 15 feet

So, we have a sequence 5, 10, 15, 20, 25....

This shows that worm climbs daily 5 feet.

Therefore, the number of days taken by worm to climb 37 feet

= 37/number of feet travel by worm each day

[tex]=\frac{37}{5}\\ =7.4 days[/tex]

Hence, Bruce's worm will take total 7.4 days to get to the top of the well.

Find out more information about sequence here:

https://brainly.com/question/19819125

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