Will do it backward - the length of the longer leg of triangle ABC = BCconsider one of the small triangles: sin30 = 10/BCso BC = 10/sin30 = 10/0.5 = 20
the length of the shorter leg of triangle ABC = ACconsider the other small triangles: sin60 = 10/ACso AC = 10/sin60 = 10/0.866 = 11.55
the length of the hypotenuse of triangle ABC = AB= sqrt (BC^2 + AC^2) = sqrt (20^2 +11.55^2)= 23.09
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