Draw two isosceles triangles, ∆ABC and ∆ADC with common base AC . Vertexes B and D are in the opposite semi-planes determined by AC . Draw the line segment BD . Prove: AC ⊥ BD . How do I solve this? What is the answer?
There is a
picture provided below and you can clearly see that AC ⊥ BD. Since AC is the base line and BD are
put on the opposite ends, there is no more explanation needed but the drawing
and the given itself.
