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What is the approximate length of the midsegment parallel to BC.
A) 4.5
B) 4.9
C) 5.6
D) 6.2

Coordinates are B(-6,1) C(5,-1) please help  there is another point A(3,7) just in case u need it 

Respuesta :

BeccaK2002
The answer is C, 5.6 and I hope this is the question you wanted me to answer...

Answer:

Step-by-step explanation:

Alright, lets get started.

There are two points B (-6, 1) and C (5, -1)

The formula for distance between both points is :

[tex]d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]

[tex]BC = \sqrt{(5+6)^2+(-1-1)^2}[/tex]

[tex]BC = \sqrt{(11)^2+(-2)^2}[/tex]

[tex]BC = \sqrt{121+5}[/tex]

[tex]BC = \sqrt{125}[/tex]

[tex]BC = 11.180[/tex]

So, its midsegment will be half of BC.

So midsegment = [tex]\frac{11.180}{2}=5.59[/tex]

Hence the answer is 5.6   :    Answer

Hope it will help :)

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