Emily has 32 grams of a 25% sugar syrup, but this is just too sweet for her! How much pure water should she add to have a 10% syrup?

Respuesta :

By this information, we know: (just so you know, when I will write the equation, the multiplication sign will be ^)

25%+0%=10%
32g    xg   (32+x)g
Now, we create an equation:

(0.25^32)+(0^x)=0.1^(32+x)
8+0=3.2+0.1x
8=3.2+0.1x
4.8=0.1x
48=x
Answer: 48 gram.

48 grams of water is added to the syrup solution.

Percentage

It represents the x value of something out of 100 is called percentage.

Given

32 gram of a 25% sugar syrup.

To find

How much pure water should she add to have a 10% syrup?

How to calculate?

Let x gram of water is added.

25% + 0% = 10%

(32)g   (x)g  (x+32)g

Now we create the equation.

[tex]\begin{aligned} (0.25*32) + (0*x) &= [(x+32)*0.1]\\8 + 0 &= 0.1x + 3.2\\8 - 3.2 &= 0.1x\\4.8 &= 0.1x\\x &= \dfrac{4.8}{0.1} \\x &= 48\\\end{aligned}[/tex]

Thus, 48 grams of water is added to the syrup solution.

More about the Percentage link is given below.

https://brainly.com/question/8011401