Respuesta :
The equation of a straight line is given by:
y = mx + c
where m is the slope and c is the y-intercept.
From the given graph, the y-intercept is 1.
The slope of a straight line is given by:
[tex]m= \frac{y_2-y_1}{x_2-x_1} [/tex]
Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are two points on the line.
From the graph, (0, 1) and (14, 8) are two points on the line, thus:
[tex]m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2} [/tex]
Therefore, the equation representing the graph is [tex]y= \frac{1}{2} x+1[/tex]
y = mx + c
where m is the slope and c is the y-intercept.
From the given graph, the y-intercept is 1.
The slope of a straight line is given by:
[tex]m= \frac{y_2-y_1}{x_2-x_1} [/tex]
Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are two points on the line.
From the graph, (0, 1) and (14, 8) are two points on the line, thus:
[tex]m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2} [/tex]
Therefore, the equation representing the graph is [tex]y= \frac{1}{2} x+1[/tex]
The answer to this is a: y=1/2 x+1
i completed the test.
Hope i helped
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