Find the coordinates of point P
P
along the directed line segment AB
AB
, from A(1, 6)
A(1, 6)
to B(−2,−3)
B(−2,−3)
, so that the ratio of AP
AP
to PB
PB
is 5
5
to 1
1
.

Question

HBon HBon

18-11-2017
Mathematics

contestada

Find the coordinates of point P
P
along the directed line segment AB
AB
, from A(1, 6)
A(1, 6)
to B(−2,−3)
B(−2,−3)
, so that the ratio of AP
AP
to PB
PB
is 5
5
to 1
1
.

Respuesta :

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tynollette tynollette · Answer 1 · 2017-11-18T03:54:10+01:00

Here is the formula for finding a partitioning point:
x=x1+k(x2-x1), y=y1+k(y2-y1)
k is the ratio of the segment from the beginning point to the partitioning : the whole segment. In this case, k=AP:AB=5/16
so x=1+(5/16)*(-2-1)=1/16
y=6+(5/16)(-3-6)=51/16
so the answer is (-1/16, 51/16)

Please double check my calculation by yourself.

refer to this website for the formula and how to find k:

"This ratio is called k, and is determined by writing the numerator over the sum of the numerator and the denominator of the original ratio."
https://cobbk12.blackboard.com/bbcswebdav/institution/eHigh%20School/Courses/CCVA%20CCGPS%20Coordina....

Find the coordinates of point P P along the directed line segment AB AB , from A(1, 6) A(1, 6) to B(−2,−3) B(−2,−3) , so that the ratio of AP AP to PB PB is 5 5 to 1 1 .

Respuesta :

Otras preguntas

Find the coordinates of point P
P
along the directed line segment AB
AB
, from A(1, 6)
A(1, 6)
to B(−2,−3)
B(−2,−3)
, so that the ratio of AP
AP
to PB
PB
is 5
5
to 1
1
.