Square EFGH has vertices: E = (-1,1), F = (-1,2), G = (-2,1), H = (-2, 2). In which quadrant will the image of vertex E' be if the square is rotated 270° clockwise about the origin O?
If we were to imagine a single point (1,1) which is in quadrant 1, and we rotate it 90o then we get a negative x. Another 90o then both x and y is negative. another 90 (270) and we get a negative y.
