Let the basis for the calculation of the molar mass of the mellaprotein be 1 mole. If x is the mass of 1 mole of the substance then,
Each of the mole of iron has a mass of 55.845 g/mol.
(4 mols of Fe)(55.845 g/ mol) = 223.38 grams
This mass is 0.60% of the total mass of the mellaprotein.
x = (223.38 grams) / (0.60/100) = 37230 g
Answer: 37230 grams