A sample of a gas originally at 29 °c and 1.25 atm pressure in a 3.0 l container is allowed to contract until the volume is 2.2 l and the temperature is 11 °c. the final pressure of the gas is ________ atm.
Answer:
1.6 atm.
pV/T = constant.
(1.25 * 3.0)/(273+29) <-- work in Kelvin
This gives you the constant.
Then you want p
So p = (T*constant)/V
= (284*0.0124)/2.2
I get = 1.6atm
