Respuesta :

6x+10y=20
10y=-6x+20
y=-6/10x+20/10
y=-3/5x+2

5x-3y=21
-3y=21-5x
y=21/-3+-5/-3x
y=3/5x-7


Two lines are Perpendicular

Answer:

Perpendicular

Step-by-step explanation:

General equation of line: [tex]y=mx+c[/tex]

Line 1: 6x+10y=20

Convert in general equation

[tex]10y = 20-6x[/tex]

[tex]y = \frac{20-6x}{10}[/tex]

[tex]y =2-\frac{6}{10}x[/tex]

[tex]y =2-\frac{3}{5}x[/tex]

Line 2: 5x-3y=21

Convert in general equation

[tex]5x-21=3y[/tex]

[tex]\frac{5x-21}{3}=3y[/tex]

[tex]\frac{5}{3}x-7=3y[/tex]

if slopes are equal then the lines are parallel

If the product of slopes is -1 then they are perpendicular

Since[tex]\frac{-3}{5} \neq \frac{5}{3}[/tex]

So, lines are not parallel

[tex]\frac{-3}{5} \times \frac{5}{3}[/tex]

[tex]-1[/tex]

Since the product of slopes is -1

Hence the given lines are perpendicular