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rgwoot
For the point P(−19,18) and Q(−14,23)​, find the distance​ d(P,Q) and the coordinates of the midpoint M of the segment PQ.
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The distance​ d(P,Q) is: 7.07

The midpoint of the segment PQ is: (-16.5, 20.5).

Distance and Midpoint Formula

Distance formula = [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex].

Midpoint formula = [tex](x, y) = (\frac{x_2 + x_1}{2}, \frac{y_2 + y_1}{2})[/tex]

Given:

P(−19,18) and Q(−14,23)​

Let,

P(−19,18) = (x1, y1)

Q(−14,23)​ = (x2, y2)

Therefore:

[tex]PQ = \sqrt{(-14 - (-19))^2 + (23 - 18)^2}\\\\\mathbf{PQ = 5\sqrt{2} = 7.07}[/tex]

Midpoint, M of PQ:

[tex]M(x, y) = (\frac{-14 + (-19)}{2}, \frac{23 + 18}{2})\\\\\mathbf{M(-16.5, 20.5)}[/tex]

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https://brainly.com/question/19149725