Respuesta :
For the point P(−19,18) and Q(−14,23), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

The distance d(P,Q) is: 7.07
The midpoint of the segment PQ is: (-16.5, 20.5).
Distance and Midpoint Formula
Distance formula = [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex].
Midpoint formula = [tex](x, y) = (\frac{x_2 + x_1}{2}, \frac{y_2 + y_1}{2})[/tex]
Given:
P(−19,18) and Q(−14,23)
Let,
P(−19,18) = (x1, y1)
Q(−14,23) = (x2, y2)
Therefore:
[tex]PQ = \sqrt{(-14 - (-19))^2 + (23 - 18)^2}\\\\\mathbf{PQ = 5\sqrt{2} = 7.07}[/tex]
Midpoint, M of PQ:
[tex]M(x, y) = (\frac{-14 + (-19)}{2}, \frac{23 + 18}{2})\\\\\mathbf{M(-16.5, 20.5)}[/tex]
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