The special drink of the month was iced mocha. The shop sold 5 times as many ice mochas in one week as hot mochas. How many more iced mochas were sold than hot mochas in 4 weeks? Explain?

There’s a picture of the table

The special drink of the month was iced mocha The shop sold 5 times as many ice mochas in one week as hot mochas How many more iced mochas were sold than hot mo class=

Respuesta :

200 +5(200) = 1200 mochas a week in total
They sold 1000 iced mocha in a week
200 x 4=800 hot mochas in 4 weeks
1000 x 4=4000 iced mochas in 4 weeks
They sold 4000-800= 3200 more iced mochas in 4 weeks

Answer:

533 iced mochas were sold more than the hot mochas.

Step-by-step explanation:

We are given the following information in the question:

Let x be the number of hot mochas sold and y be the number of iced mochas sold.

Total number of mochas sold in a week = 200

Thus, this can be represented in the form of equation as:

[tex]x+y = 200[/tex]

The shop sold 5 times as many ice mochas in one week as hot mochas.

Thus, we can write this in the form of equation as:

[tex]y = 5x[/tex]

Solving the two equation:

[tex]x + 5x = 200\\6x = 200\\\\x = \displaystyle\frac{200}{6}[/tex]

[tex]y = \displaystyle\frac{1000}{6}[/tex]

Now, number of hot mochas sold in 4 week =

[tex]\text{Number of hot mochas sold in 1 week}\times 4 =\\\\ \displaystyle\frac{200}{6}\times 4 = \frac{800}{6}[/tex]

Number of iced mochas sold in 4 weeks =

[tex]\text{Number of iced mochas sold in 1 week}\times 4 =\\\\ \displaystyle\frac{1000}{6}\times 4 = \frac{4000}{6}[/tex]

Number of iced mochas sold more than hot mochas in 4 weeks =

[tex]\text{Number of iced mochas sold in 4 weeks} - \text{Number of hot mochas sold in 4 weeks}\\\\= \displaystyle\frac{4000}{6}- \frac{800}{6} = \frac{3200}{6} = 533.33 \approx 533[/tex]

Hence, 533 iced mochas were sold more than the hot mochas.