From a boat on the lake, the angle of elevation to the top of a cliff is 11°50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)?

Respuesta :

Answer:

x = 1568*tan(11°50')

x = 328.5 feet

x = 329 feet

Step-by-step explanation:

The height of the cliff is 328 feet.

Conversion of minutes into degrees

There are sixty minutes in every degree, by definition. To convert a number of minutes to degrees, divide the number of minutes by sixty.

According to the question

From a boat on the lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)

Note that 11°50' is just 11 degrees and 50 minutes

60 minutes = 1 degree,

thus 50 minutes = x degree

= [tex]\frac{50}{60}[/tex] degrees

= 0.83°

Hence: 11°50' = 11.83°.

We solve using Trigonometric function of tan

[tex]tan \theta[/tex] = [tex]\frac{Opposite}{Adjacent}[/tex]

[tex]\theta[/tex] = 11.83°

Adjacent = 1568 feet

Opposite = Height of the cliff = x

[tex]tan 11.38^{0} = \frac{x}{1568}[/tex]

Cross Multiply

x = [tex]tan 11.83\times 1568[/tex]

x = 328.429195 feet

Approximately  x = 328 feet (nearest foot)

Hence, the height of the cliff is 328 feet.

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