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Ryan rolls a steel ball horizonyally at 0.8m/s from a top of a lab table that is 0.95 m high.

a) How long will it take the stone to strike the ground?

b) How far from the edge of the table did the ball travel?

Respuesta :

theandysanchez
for part a we can use the kinematic formula distance= velocity(initial)*time+1/2*acceleration*time^2
we know there is only velocity in the horizontal and none in the vertical so v initial in this case is 0, acceleration is gravity =9.81m/s^2
plug in .95=(1/2)*9.81*t^2 solve for t
t=.44seconds 
Now for part b we know there is no horizontal acceleration so distance= velcoity* time
we will use horrizontial velocity and the time we just found
distance= .8m/s*.44seconds
=.35 meters

okpalawalter8

We have that for the Question "Ryan rolls a steel ball horizontally at 0.8m/s from a top of a lab table that is 0.95 m high." it can be said that

it will take the stone t=0.44sec to strike the ground and the ball will travel r=0.352m  from the edge

From the question we are told

Ryan rolls a steel ball horizontally at 0.8m/s from a top of a lab table that is 0.95 m high.  

a) How long will it take the stone to strike the ground?  

b) How far from the edge of the table did the ball travel?

a

Generally the Newtons equation for the motion  is mathematically given as

s=ut+1/2at^2

Therefore

0.95=0+1/2(9.8)t^2

t=0.44sec

b)

Generally the Newtons equation for the Range  is mathematically given as

R=0.8*0.44

r=0.352m

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https://brainly.com/question/23379286

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