Answer:
[tex]\sqrt{3}[/tex] is the required quotient.
Step-by-step explanation:
We have been given the expression:
[tex]\frac{3\sqrt{60}}{3\sqrt{20}}[/tex]
Cancel the common term which is 3 we will be left with
[tex]\frac{\sqrt{60}}{\sqrt{20}}[/tex]
[tex]\sqrt{60}[/tex] can be written as after prime factorization is:
[tex]2\sqrt{15}[/tex]
And [tex]\sqrt{20}[/tex] can be written as after prime factorization is:
[tex]2\sqrt{5}[/tex]
Hence, the given expression would become after 2 gets cancel from numerator and denominator:
[tex]\frac{\sqrt{3}\cdot \sqrt{5}}{\sqrt{5}}[/tex]
Quotient is the answer we get after dividing numerator by denominator and cancel common term which is [tex]\sqrt{5}[/tex]
[tex]\sqrt{3}[/tex] is the required quotient.
