Mr. Bobby plans to spend no more than $200 on pizza and soda for a party. Each pack of soda costs $5.00 and each pizza costs $8.00. What inequality could Mr. Bobby use to determine how many packs of soda, s, and how many pizzas, p, he can buy?

Respuesta :

One side of the inequality would be the final amount, $200 and we would use 200≥ since he wants to spend no more than that. The other side of the inequality would be the amount spent on pizzas and sodas. Since each pizza is $8.00, that term would be 8p or $8.00 x the number of pizzas. Sodas would be 5s for the same reason. So putting this all together, the inequality would be: 200 ≥ 8p + 5s

Answer:

The inequality to determine the number of packs of pizzas and soda is [tex]8p+5s\leq 200[/tex].

Step-by-step explanation:

Given:

The cost of pizza is, $8.00.

The cost of soda is, $5.00.

Total cost Mr. Bobby can bear is, $200.

Let number of pizza purchased by Mr. Bobby be p. And s be the number of soda.

Since, Mr. Bobby cannot spend more than $200. Means he can spend less than or equal to $200.

So, inequality is,

[tex]8p+5s\leq 200[/tex]

Thus, the required inequality is [tex]8p+5s\leq 200[/tex].

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https://brainly.com/question/24853349?referrer=searchResults