Respuesta :
Answer is: the percent composition of Hg in the compound is 71.5%.
Balanced chemical reaction: Hg + Br₂ → HgBr₂.
m(Hg) = 60.2 g; mass of the mercury.
m(Br₂) = 24.0; mass of the bromine.
m(HgBr₂) = m(Hg) + m(Br₂).
m(HgBr₂) = 60.2 g + 24 g.
m(HgBr₂) = 84.2 g; mass of the compound.
ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.
ω(Hg) = 60.2 g ÷ 84.2 g · 100%.
ω(Hg) = 71.5%.
The percentage composition of Hg in the given compound is [tex]\boxed{71.5{\text{ \% }}}[/tex].
Further explanation:
The amount of substance that is present in any mixture is known as concentration. It is expressed in different forms, called as concentration terms. Most of the commonly used concentration terms are as follows:
1. Molality
2. Mole fraction
3. Molarity
4. Parts per million
5. Mass percent
6. Volume percent
7. Percentage composition
The given reaction occurs as follows:
[tex]{\text{Hg}} + {\text{B}}{{\text{r}}_2} \to {\text{HgB}}{{\text{r}}_{\text{2}}}[/tex]
The formula to calculate the percentage composition of Hg is as follows:
[tex]{\text{Percentage composition of Hg}} = \left( {\dfrac{{{\text{Mass of Hg}}}}{{{\text{Mass of HgB}}{{\text{r}}_2}}}} \right){\text{100 \% }}[/tex] …… (1)
The formula to calculate the mass of [tex]{\text{HgB}}{{\text{r}}_{\text{2}}}[/tex] is as follows:
[tex]{\text{Mass of HgB}}{{\text{r}}_{\text{2}}} = {\text{Mass of Hg}} + {\text{Mass of B}}{{\text{r}}_{\text{2}}}[/tex] …… (2)
The mass of Hg is 60.2 g.
The mass of [tex]{\text{B}}{{\text{r}}_{\text{2}}}[/tex] is 24 g.
Substitute these values in equation (2).
[tex]\begin{aligned}{\text{Mass of HgB}}{{\text{r}}_{\text{2}}} &= 60.2{\text{ g}} + {\text{24 gAC}}\\&= {\text{84}}{\text{.2 g}}\\\end{aligned}[/tex]
The mass of Hg is 60.2 g.
The mass of [tex]{\text{HgB}}{{\text{r}}_{\text{2}}}[/tex] is 84.2 g.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Percentage composition of Hg}} &= \left( {\frac{{{\text{60}}{\text{.2 g}}}}{{{\text{84}}{\text{.2 g}}}}} \right){\text{100 \% }}\\&= {\text{71}}{\text{.49 \% }}\\&\approx {\text{71}}{\text{.5 \% }}\\\end{aligned}[/tex]
Therefore the percentage composition of Hg in the compound is 71.5 %.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: Hg, Br2, HgBr2, 60.2 g, 24 g, 84.2 g, mass of Hg, mass of Br2, mass of HgBr2, 71.5 %, concentration terms, molality, molarity, mole fraction, percentage composition.
