Respuesta :

randgh
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

the sum is less than 8, we will remove  s which have sum of 8 or more
we have 21

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) 
(3,1) (3,2) (3,3) (3,4)
(4,1) (4,2) (4,3)
(5,1) (5,2)
(6,1)

the doubles  (1.1)   (2.2)  (3.3) 
So 3 out of the 21 are doubles

3/21 = 1/7 
abidemiokin

The probability that doubles are rolled, given that the sum on the two dice is less than 8 is 3/21

What is probability?

Probability is the likelihood or chance that an event will occur. Mathematically:

Probability = Expected outcome/Total outcome

If the sum of the two dice rolled is less than 8, then the outcome will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,3) (3,4)

(4,1) (4,2) (4,3)

(5,1) (5,2)

(6,1)

n(S) = 21

Doubles that are rolled = (1.1)   (2.2)  (3.3)

n(E) = 3

Find the probability

Pr(double are rolled) = 3/21

Hence the probability that doubles are rolled, given that the sum on the two dice is less than 8 is 3/21

Learn more on probability here: https://brainly.com/question/24756209

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