Enter the complete ionic equation to show the reaction of aqueous lead(ii) nitrate with aqueous potassium sulfate to form solid lead(ii) sulfate and aqueous potassium nitrate. express your answer as a chemical equation. identify all of the phases in your answer.

Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)

Total ionic equation:

Pb 2+ (aq) + 2NO3- (aq) + 2K+ (aq) + SO4 2- (aq) ---------> PbSO4 + 2K+ (aq) + 2NO3- (aq)

For the net ionic equation cancel out species found on both sides to get:

Pb 2+ (aq) + SO4 2- (aq) ----------> PbSO4(s)

Note aqueous species dissolve and are separated into their ions but solid ones do not and simply precipitate out of solution.

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dsdrajlin dsdrajlin · Answer 2 · 2021-10-01T20:45:39+02:00

The complete ionic equation for the reaction of aqueous lead (II) nitrate with aqueous potassium sulfate to form solid lead (II) sulfate and aqueous potassium nitrate is:

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + SO₄²⁻(aq) ⇒ PbSO₄(s) + 2 K⁺ + 2 NO₃⁻(aq)

Let's consider the molecular equation that occurs between aqueous lead (II) nitrate and aqueous potassium sulfate to form solid lead (II) sulfate and aqueous potassium nitrate. This is a double displacement reaction.

Pb(NO₃)₂(aq) + K₂SO₄(aq) ⇒ PbSO₄(s) + 2 KNO₃(aq)

The complete ionic equation includes all the ions and the molecular species.

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + SO₄²⁻(aq) ⇒ PbSO₄(s) + 2 K⁺ + 2 NO₃⁻(aq)

The complete ionic equation for the reaction of aqueous lead (II) nitrate with aqueous potassium sulfate to form solid lead (II) sulfate and aqueous potassium nitrate is:

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + SO₄²⁻(aq) ⇒ PbSO₄(s) + 2 K⁺ + 2 NO₃⁻(aq)

You can learn more about ionic equations here: https://brainly.com/question/21883718