How much heat does your body lose when 3.45 g of sweat evaporates from your skin at 25 âc? (assume that the sweat is only water.) the heat of vaporization of water at 25 âc is 44.0 kj/mole?
Water has a Mol.mass of 18g/mol. (2 x 1:H) + (1 x O:16) = 18.
Mass / mol.mass = moles.
3.45g / 18g/mol. = 0.192 moles of sweat.
0.192mol. x 44.0kJ/mol = 8.43kJ of heat released from the body.
