Respuesta :

mussabakkari
STP = Standard Temperature and pressure 
T = 0°C or 273.15 K 
P = 1 atm 

Given V = 237.8 L 
and we know gas constant, R = 0.082 L atm / K mol 

PV = nRT 
n = PV/RT = (1 x 237.8) / (0.082 x 273.15) = 10.62 mol 

********* 
Quicker way is to do as "Roger the Mole" did above 

At STP 1 mol of any gas occupies 22.4 L 
then moles of CO2 = (237.8 L) / (22.4 L/mol) = 10.62 mol
mahima6824soni

The moles of carbon dioxide contained in 237.8 l at stp is 10.62 mol.

What are moles?

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

By ideal gas law:

PV = nRT

Given the volume is 237.8 L

The gas constant is  R = 0.082 L atm / K mol

Standard temperature 273.15 K, pressure is 1 atmp

Putting the values in the equation:

n = PV/RT = (1 x 237.8) / (0.082 x 273.15) = 10.62 mol

Thus, the mole is 10.62 mol

Learn more about moles

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