What is ax, the x-component of the object's acceleration? express your answer to two significant figures and include the appropriate units?

Respuesta :

Answer: F = ma Fx = max WHERE: Fx = forces in the x direction m = mass ax = acceleration in the x direction If we look at the figure, there are only two forces in the x direction. The first force is the x component force 4.0 N acting to the right, denoted as +4.0 N. The second force is the 2.0 N force acting to the left, denoted as -2.0 N. Fx = max 4.0 N - 2.0 N = (7.8 kg)*ax 2.0 N = (7.8 kg)*ax ax = 0.25641 m/s^2 Because the question is asking you to write it to two significant figures, ==>ax = 0.26 m/s^2

The X-component of acceleration of the body is the rate of change of velocity of the body in the direction of X-axis.

Further Explanation:

Consider a body is moving with a uniform acceleration in [tex]x-y\text{ plane}[/tex].

Here, [tex]x[/tex] represents the X-axis and [tex]y[/tex] represents the Y-axis of the plane.

The rate of change of position of the body on x-y plane can be specified by the rate of change of position in the direction of x-axis and y-axis.

[tex]\vec r=\left( {x\hat i+y\hat j} \right){\text{ m}}[/tex]

Here, [tex]\vec r[/tex] is the position vector of the body, [tex]x[/tex] is the distance measure from origin in X-direction and [tex]y[/tex] is the distance measure from origin in Y-direction.

Similarly, the rate of change of velocity of the body can be specified by rate of change of velocity in direction of X-axis and Y-axis.

[tex]\dfrac{{d\vec v}}{{dt}}=\left( {\left( {\dfrac{{d{v_x}}}{{dt}}} \right)\hat i + \left( {\dfrac{{d{v_y}}}{{dt}}} \right)\hat j} \right){{{{\text{ m}}} \mathord{\left/ {\vphantom {{{\text{ m}}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}^2}[/tex]                                 …… (1)

Here, [tex]\dfrac{{d\vec v}}{{dt}}[/tex] is the rate of change of velocity of body, [tex]\left( {\dfrac{{d{v_x}}}{{dt}}} \right)[/tex] is the rate of change of velocity in direction of X-axis and [tex]\left({\dfrac{{d{v_y}}}{{dt}}}\right)[/tex] is the rate of change of velocity in direction of Y-axis.

From the definition of acceleration,

The rate of change of velocity is acceleration and rate of change of velocity in X-direction is the acceleration in X-direction and rate of change of velocity in Y-direction is the acceleration in Y-direction.

So, equation (1) can be written as,

[tex]\boxed{a=\left( {{a_x}\hat i + {a_y}\hat j} \right){{{\text{ m}}} \mathord{\left/ {\vphantom {{{\text{ m}}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}}[/tex]

Here, [tex]a[/tex] represents the actual or resultant acceleration of the body, [tex]{a_x}[/tex] is the acceleration of the body in X-direction or rate of change of velocity in X-direction, [tex]{a_y}[/tex] is the acceleration of the body in Y-direction or rate of change of velocity in Y-direction.

Learn More:

1. Motion of a ball under the acceleration due to gravity https://brainly.com/question/10934170

2. A 30kg box being pulled on a carpeted floor https://brainly.com/question/7031524

3. A 50-kg meteorite moving at 1000 m/s strikes Earth https://brainly.com/question/6536722

Answer Detail:

Grade: Senior school

Chapter: Kinematics

Subject: Physics

Keywords:

x-component of acceleration, ax, component, acceleration, velocity, rate of change, time, X-axis, X-direction.

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