Respuesta :

W0lf93
mass B/molar mass A = (rate A/rate B)^2. we know our unknown gas (A) effuses at .797 times our known gas (B) so rate A/rate B = .797 so 0.797^2 = 28 / molar mass A Molar mass A = 28 / 0.635 = 44.09 g / mole Molar mass is 44.09 g/mol

Answer: Molar mass of unknown gas=43.75[tex]gmol^{-1}[/tex]

Explanation: Graham's Law states that the rate of effusion of gas is inversely proportional to the square root of their atomic masses.

[tex]{\text {Rate of effusion}}=\frac{1}{\sqrt\text {Molecular mass}}[/tex]

[tex]\frac{R_1}{R_2}=\sqrt\frac{M_2}{M_1}[/tex]

[tex]R_1[/tex]= rate of effusion of nitrogen = x

[tex]R_2[/tex]= rate of effusion of unknown gas = 0.797x

[tex]M_1[/tex]= Molecular mass of nitrogen[tex](N_2)[/tex] = 28g

[tex]M_2[/tex]= Molecular mass of unknown gas

[tex]\frac{x}{0.797x}=\sqrt\frac{M_2}{28gmol^{-1}}[/tex]

[tex]M_2=43.75gmol^{-1}[/tex]


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