The first step is to find the installation cost of each flooring.
let i be the instalation fee, and i2 and i3 correspond to scenarios 2 and 3
(1.73)(120)+i=740.40
(4.98)(200)+i2=1,688.00
(2.48)(180)+i3=928.80
i=532.8
i2=692.00
i3=482.4
ok, so we have the total installation cost for each room. Now we divide that by square feet.
532.8/120=4.44
692.00/200=3.46
482.4/180=2.68
Ordering that from least to greatest, you get Berber carpet, hand-scraped hardwood, and slate tile, which has the greatest installation fee.
Brainliest answer?