We want to find y from the equation
[tex] \frac{3}{y-2} =8[/tex]
Multiply each side by (y - 2).
[tex](y-2).( \frac{3}{y-2)}) = 8(y-2) [/tex]
Note that (y-2) in the numerator and denominator cancel out on the left side.
Therefore
3 = 8(y - 2)
3 = 8y - 16
Add 16 to each side.
3 + 16 = 8y - 16 + 16
19 = 8y
Divideach side by 8.
19/8 = y
Answer: [tex]y= \frac{19}{8} [/tex]
