Respuesta :
Multiply out the product on the left side:
3{x-2}+1=3x-5 becomes 3x-6 + 1 = 3x -5
3x-5 = 3x - 5
This is always true, regardless of the value of x. Thus, this equation has infinitely many solutions.
3{x-2}+1=3x-5 becomes 3x-6 + 1 = 3x -5
3x-5 = 3x - 5
This is always true, regardless of the value of x. Thus, this equation has infinitely many solutions.