HELP ASAP PLZ

Jane has 38 marbles of the same shape and size in a box. The colors and amounts of the marbles are shown below:

•14 white marbles
•9 gray marbles
•15 blue marbles

Without looking in the box, Jane takes out a marble at random. She then replaces the marble and takes out another marble from the box. What is the probability that Jane takes out a gray marble in both draws?

9/38x8/37 =72/1406
9/38+8/37 =637/1406
9/38+9/38 =684/1444
9/38x9/38 =81/1444

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bannapotts2177 bannapotts2177 · Answer 1 · 2017-10-19T20:13:43+02:00

9/38 x 9 /38 =81/144 both of the events are indepent

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throwdolbeau throwdolbeau · Answer 2 · 2019-05-21T09:22:35+02:00

Answer:

The correct option is D. 9/38x9/38 =81/1444

Step-by-step explanation:

Total number of marbles in the bag = 38

Number of white marbles in the bag = 14

Number of gray marbles in the bag = 9

Number of blue marbles in the bag = 15

We need to find the probability that Jane takes out a gray marble in both draws

[tex]\text{Probability that Jane draws gray marble in first draw = }\frac{9}{38}[/tex]

Given that : Then Jane replaces the marble for the second draw

[tex]\text{Probability that Jane draws gray marble in second draw = }\frac{9}{38}[/tex]

[tex]\text{Probability that Jane draws gray marble in both draws = }\frac{9}{38}\times \frac{9}{38}[/tex]

[tex]\text{Probability that Jane draws gray marble in both draws = }\frac{81}{1444}[/tex]

Therefore, The correct option is D. 9/38x9/38 =81/1444