divide 1006 by 12
1006 / 12 = 83.833
so 83 full trucks
83 *12 = 996
1006-996 = 10 cars will be on the last truck
Answer:
Last one truckload will contain 10 cars and total no. of truckloads required is 84
Step-by-step explanation:
Given :an auto transport truck holds 12 cars. A car dealer plans to bring in 1006 new cars in June and July.
To Find : . if an auto transport truck is filled for each delivery, except for the last one, how many full truckloads are needed and how many cars will be in the last truck?
Solution :
Let no. of truckloads used = x
Since each truckloads can hold 12 cars
So, x truckloads can hold 12x cars
since there are total 1006 cars
So, 12x=1006
[tex]x=\frac{1006}{12}[/tex]
[tex]x = 83.83[/tex]
So, No. of fully filled truckloads is 83
since 1 truckload holds 12 cars
So, 83 truckloads hold cars = 12*83 =996
Thus 996 cars are loaded in 83 truckloads
So, remaining cars = 1006-996 = 10 cars
So, one more truckload is required to load these remaining 10 cars.
So, last one truckload will contain 10 cars
So, total no. of truckloads requires = 83+1=84
Hence last one truckload will contain 10 cars and total no. of truckloads required is 84
