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A dilation with a scale factor of 15 and centered at the origin is applied to MN¯¯¯¯¯¯¯ with endpoints M(−2, −4) and N(1, 5) .

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A dilation with a scale factor of 15 and centered at the origin is applied to MN with endpoints M2 4 and N1 5 Drag and drop to match the correct coordinates wit class=

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Answer:

(-2/5, -4/5); (1/5, 1)

Step-by-step explanation:

We multiply the x- and y-coordinates of both points by the scale factor, 1/5:

M' = (-2(1/5), -4(1/5)) = (-2/5, -4/5)

N' = (1(1/5), 5(1/5)) = (1/5, 5/5) = (1/5, 1)

A scale factor is a number that multiplies (or "scales") the value of a quantity. The dilation of the points MN to M'N' is [tex](-\dfrac{2}{5}, -\dfrac{4}{5})[/tex] and [tex](\dfrac{1}{5}, 1)[/tex] respectively.

What is the scale factor?

A scale factor is a number that multiplies (or "scales") the value of a quantity. The "C" in y = Cx, for example, is the scaling factor for x. The factor would be 5 if the equation was y = 5x.

As it is given that the dilation of points is with a scale factor of 1/5 that is centred at the origin, therefore, the dilation of the points can be written as,

[tex]M' = [(-2 \times \dfrac{1}{5}), (-4 \times \dfrac{1}{5})] = (-\dfrac{2}{5}, -\dfrac{4}{5})[/tex]

[tex]N' = [(1 \times \dfrac{1}{5}), (5 \times \dfrac{1}{5})] = (\dfrac{1}{5}, 1)[/tex]

Hence, the dilation of the points MN to M'N' is [tex](-\dfrac{2}{5}, -\dfrac{4}{5})[/tex] and [tex](\dfrac{1}{5}, 1)[/tex] respectively.

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