Respuesta :
Given,
first term a₁ = k
General term;
[tex] a_{n} = 2a_{n-1} [/tex]
Hence, third term (n = 3);
[tex] a_{3} = 2 a_{3-1} = 2a_{2} = 2 * (2a_{2-1}) = 4a_{1} = 4k[/tex]
Hence, the answer is B: 4k.
first term a₁ = k
General term;
[tex] a_{n} = 2a_{n-1} [/tex]
Hence, third term (n = 3);
[tex] a_{3} = 2 a_{3-1} = 2a_{2} = 2 * (2a_{2-1}) = 4a_{1} = 4k[/tex]
Hence, the answer is B: 4k.
Answer:
option 2nd is correct
4k is the third term of the sequence.
Step-by-step explanation:
Given the statement:
[tex]a_1 = k[/tex]
[tex]a_n = 2a_{n-1}[/tex]
We have to find the third term of the sequence.
For n = 2 we have;
[tex]a_2= 2a_{2-1}[/tex]
⇒[tex]a_2= 2a_{1}[/tex]
Substitute the given value we have;
[tex]a_2 = 2 \cdot k = 2k[/tex]
For n =3,
[tex]a_3= 2a_{3-1}[/tex]
⇒[tex]a_3= 2a_{3}[/tex]
Substitute the given value of [tex]a_2[/tex] we have;
[tex]a_3= 2 \cdot 2k = 4k[/tex]
Therefore, the third term of the sequence is, 4k
