For the following reaction, what volume of NOBr can be produced from 3.8 L of Br2 (measured at the same temperature and pressure), assuming an excess of NO?
2NO(g)+Br2(g)=2NO(Br)2

In this case, since no temperature and pressure are known, one could develop the stoichiometric relationship for 1 mole of [tex]Br_2[/tex] per 2 moles of [tex]NOBr[/tex] in terms of volume as shown below because of the Avogadro's law (change in mole proportional to the change in volume at constant both pressure and temperature):

[tex]3.8LBr_2*\frac{2LNOBr}{1LBr_2} =7.6LNOBr[/tex]

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For the following reaction, what volume of NOBr can be produced from 3.8 L of Br2 (measured at the same temperature and pressure), assuming an excess of NO? 2NO(g)+Br2(g)=2NO(Br)2

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For the following reaction, what volume of NOBr can be produced from 3.8 L of Br2 (measured at the same temperature and pressure), assuming an excess of NO?
2NO(g)+Br2(g)=2NO(Br)2