Respuesta :
To find this z-score, locate the score on the table such that the area of the curve to the right is 0.37. This is similar to the 37th percentile. After locating it, you will see that the z-score is 0.3319.
Using the standard normal table, it is found that the z-score is z = 0.33.
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In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the standard normal table and find the p-value associated with this z-score, which is the percentile of X.
- This p-value is the left-tailed area.
- The right-tailed area is 1 subtracted by the p-value.
In this problem:
- Right-tailed area of 0.37, thus the p-value is of 1 - 0.37 = 0.63.
- Looking at the standard normal table, the z-score is z = 0.33.
A similar problem is given at https://brainly.com/question/7001627