A 231-ω and a 206-ω resistor are connected in series across an unspecified power supply. if the current through the 231-ω resistor is 0.39 a, what is the exact current (in
a.through the 206-ω resistor? do not include units with your answer.

Respuesta :

As we know same current flows in a series circuit
so in this case current through both the resistors is equal, which is 0.39 a....

The characteristics of series circuits, we can find that the current in the two resistances the same, the answer is:

  • i = 0.39 A flows in the 206 Ω resistor

Electric circuits are a system formed by resistors, capacitors and coils, through which the electric current flows, these circuits can be classified:

  • Parallel circuits. In these circuits there are several branches in such a way that the current is divided between each branch according to its resistance, the advantage that if one branch is broken by the others, electricity can continue to flow.
  • Series cicuits In this type of circuit there is only one path for the current, which is why when it breaks, the current in the entire circuit is interrupted.

In this case it is indicated that we have a series circuit, for which all the current must flow through the path, consequently all the current of the circuit must pass through the two resistors.

In conclusion, using the characteristics of series circuits, we find that the current in the two resistances the same, the answer is:

  • i = 0.39 A flows in the 206Ω  resistor

Learn more about series circuits here:

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