four brothers invested in a restaurant. One brother invested $140000. Two brothers invested in the ratio x:2x, and the fourth brother invested an amount equal to the three brothers combined. the total investment was $1600000. How much did each brother invest?

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19-10-2017
Mathematics

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four brothers invested in a restaurant. One brother invested $140000. Two brothers invested in the ratio x:2x, and the fourth brother invested an amount equal to the three brothers combined. the total investment was $1600000. How much did each brother invest?

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Timothyle211 Timothyle211 · Answer 1 · 2017-10-29T23:19:31+01:00

Hope its right.

1. What you want to do is do is to know 2x is the ratio and x; $140,000 is the 1 brother investment and total is $1,600,000

2. Put them together 2x (140,000 + x + 2x) = 1600,000
3. 280,000 + 2x + 4x = 1600,000
4. 280,000 + 6x = 1600,000
5 1600,000-280,000= 1320,000 /6
6. They each invested $220,000