An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17,000 ft., what is the distance (x) from the plane (P) to the observer (O)?
20,757 feet
24,251 feet
29,639 feet
31,262 feet

Respuesta :

Answer:

here are numerous information's already given in the question. Based on those information's, the answer to the question can be easily deduced.

Angle at which the plane is flying in respect to the observer = 35 degree

Altitude at which the plane is flying = 17000 feet

The distance at which the plane is flying from the observer = x 

Then

x = 17000/sin 35

 = 17000/0.57357

 = 29638.93 feet

 = 29639 feet

From the above deduction, we can conclude that the correct option among all the options given in the question is the third option.

 

GIVE BRainliest plz

The distance between the plane and the observer is 29,638 feet.

Data;

  • Angle = 35 degrees
  • height of the plane = 17,000ft
  • distance from the plane to the observer = x

Trigonometric Ratio

This is the use of SOHCAHTOA which is the relationship between sides of a right angle triangle and it's angle.

In this case, we have the value of opposite and angle and we need to find the hypothenuse.

Using sine of the angle,

[tex]sin\theta = \frac{opposite}{hypothenuse} \\sin 35 = \frac{17000}{x}\\ x = \frac{17000}{sin35}\\ x = 29,638 feet[/tex]

The distance between the plane and the observer is 29,638 feet.

Learn more on trigonometric ratios here;

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