Respuesta :
let x and y are the integers.
the product of two integers x and y = (x)(y) = 9
and their sum = x + y = -6
y = -6 -x
now put the value of y in the product equation;
(x)(-6-x) = 9
-6x - x² -9 = 0
x²+6x + 9 = 0
x² +3x +3x + 9 = 0
x(x+3) + 3 (x+3) = 0
(x+3)(x+3) = 0
so, x+3 = 0
x = -3
So, the two integers are -3 and -3
if we multiply -3 and -3 we get answer 9
and if we add -3 and -3 we get answer -6.
the product of two integers x and y = (x)(y) = 9
and their sum = x + y = -6
y = -6 -x
now put the value of y in the product equation;
(x)(-6-x) = 9
-6x - x² -9 = 0
x²+6x + 9 = 0
x² +3x +3x + 9 = 0
x(x+3) + 3 (x+3) = 0
(x+3)(x+3) = 0
so, x+3 = 0
x = -3
So, the two integers are -3 and -3
if we multiply -3 and -3 we get answer 9
and if we add -3 and -3 we get answer -6.
The two integers whose product is 9 and whose sum is -6 are -3 and -3. -3 multiplied by -3 is 9 and -3 + -3 is -6.