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Kalahira
The charge associated with each side of an HF molecule is 6.93Ă—10â»Â˛â°C. The charge on a single electron is 1.60 x 10â»ÂąâąC. How do you find percent ionic character, and what does the value mean? 43.3% If the HF molecule were 100% ionic, the F side would have a charge of â’1, whereas the H side would have a charge of +1. Instead, the F side has a partial charge of â’ 0.433, whereas the H side has a partial charge of +0.433.
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Further Explanation

The dipole moment value of a polar compound can be used to estimate the magnitude of the ionic character of the compound. In the HF molecule if the bond is considered to be 100% ionic, the charge on the H + ion and the F- ion is 1.6 x 10-19 C. and the value of the dipole moment becomes like:

ionic = q x d

= 1.60 x 10-19 C x 91.7 x 10-12

= 1, 467 x 10 -29 C.m

= 4.40 D

Ion character == x 100% = 40.05%

so is the HF dipole moment based on the data above the HF ionic character is 40.05%

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HF ionic : https://brainly.com/question/6284826

Details

Class: college

Subject: biology

Keywords : HF, ionic, dipole, moment.