How many grams are there in 7.50 x 10^23 molecules of H2SO4

Answer:
123 g
Explanation:
1 mole of H₂SO₄ contains 6.02 × 10²³ molecules of H₂SO₄ (Avogadro's number). The moles of H₂SO₄ represented by 7.50 × 10²³ molecules of H₂SO₄ are:
7.50 × 10²³ molecules × (1 mol/ 6.02 × 10²³ molecules) = 1.25 mol
The molar mass of H₂SO₄ is 98.08 g/mol. The mass of H₂SO₄ represented by 1.25 mol is:
1.25 mol × (98.08 g/mol) = 123 g
The mass of 7.5 x 10²³ molecules of H₂SO₄ is 122.5 g.
One mole of a substance contains 6.02 x 10²³ molecules of the substance.
6.02 x 10²³ molecules --------------- one mole of H₂SO₄
7.5 x 10²³ molecules --------------------- ?
[tex]x = \frac{7.5 \times 10^{23}}{6.02 \times 10^{23}} \\\\x = 1.25 \ moles[/tex]
1 mole ------ 98 g/mol
1.25 moles ----- ?
= 1.25 x 98
= 122.5 g
Thus, the mass of 7.5 x 10²³ molecules of H₂SO₄ is 122.5 g.
Learn more about Avogadro's number here: https://brainly.com/question/8946174