[tex]\bf \qquad \textit{Continuously Compounding Earned Amount}\\\\
A=Pe^{rt}\qquad
\begin{cases}
A=\textit{accumulated amount}\to &7446.52\\
P=\textit{original amount deposited}\\
r=rate\to 4.32\%\to \frac{4.32}{100}\to &0.0432\\
t=years\to &5
\end{cases}
\\\\\\
7446.52=Pe^{0.0432\cdot 5}\implies \cfrac{7446.52}{e^{0.0432\cdot 5}}=P\implies 5999.92404\approx P[/tex]
