contestada

a soccer ball is kicked with a speed of 15.6m/s at an angle of 32.5 degrees above the horizontal. If the ball lands at the same level from which it was kicked for what amount of time was it in the air?

Respuesta :

ADD 15.6 +32.5=7605 hope i helped :)

Answer:

Time of flight, t = 1.71 seconds

Explanation:

It is given that,

Speed of the soccer ball, u = 15.6 m/s

Angle made with the horizontal, [tex]\theta=32.5^{\circ}[/tex]

Let t is the time for which the ball was in the air. The time duration for which the ball is in air is called the time of flight of the projectile. It is given by :

[tex]t=\dfrac{2u\ sin\theta}{g}[/tex]

[tex]t=\dfrac{2(15.6)\ sin(32.5)}{9.8}[/tex]

t = 1.71 seconds

So, the ball was in the air for 1.71 seconds. Hence, this is the required solution.