Respuesta :
2x^2-16x+32=0
2(x^2 - 8x + 16) = 0
2(x - 4)^2 = 0
x - 4 = 0; x = 4
answer
x = 4 is the solution
2(x^2 - 8x + 16) = 0
2(x - 4)^2 = 0
x - 4 = 0; x = 4
answer
x = 4 is the solution
Answer:
The Answer is 4
Step-by-step explanation:
2x² - 16x + 32 = 0
we would multiply 2x² and 32
= 64x²
then factorise 64x² such that the sum of the two nos = -16 AND the product of the nos = 64
the only value that satisfies this condition is -8 (-8 + -8 = -16, and -8 * -8 = 64)
- so our equation becomes
0 = 2x² - 8x -8x + 32
0 = (2x² - 8x) (-8x +32)
- we bring out common terms i.e. factorise it
2x(x - 4) -8(x - 4)
0 = (2x - 8) (x - 4)
0 = 2x - 8 or 0 = x - 4
8 = 2x or 4 = x
x = 8/2 or 4
x = 4 or 4
x = 4
hope it was clear