Respuesta :

The number line for [tex]\fbox{\begin\\\ \bf \text{option 1}\\\end{minispace}}[/tex] represents the solution for the equation [tex]|x+4|=2[/tex].

Further explanation:

The equation is given as follows:

[tex]|x+4|=2[/tex]

In the above equation [tex]||[/tex] represents the modulus function.

Modulus function is defined as a function which gives positive value of the function for any real value of [tex]x[/tex].

For example: The function [tex]y=|x|[/tex] is a modulus function in which [tex]y>0[/tex] and [tex]x<0[/tex] or [tex]x>0[/tex].

In the given equation [tex]|x+4|[/tex]  is a modulus expression.  

There are two cases formed for [tex]|x+4|[/tex].

First case:  [tex]x>-4[/tex]

If [tex]x>-4[/tex] then [tex]|x+4|\rightarrow (x+4)[/tex].

Substitute [tex]|x+4|=(x+4)[/tex] in [tex]|x+4|=2[/tex].

[tex]\begin{aligned}x+4&=2\\x&=2-4\\&=-2\end{aligned}[/tex]

Therefore, for [tex]x>-4[/tex] the value of [tex]x[/tex] which satisfies the equation [tex]|x+4|=2[/tex] is [tex]x=-2[/tex].

Second case:  [tex]x<-4[/tex]

If [tex]x<-4[/tex] then [tex]|x+4|\rightarrow -(x+4)[/tex].

Substitute [tex]|x+4|=-(x+4)[/tex] in [tex]|x+4|=2[/tex].

[tex]\begin{aligned}-(x+4)&=2\\-x-4&=2\\-x&=2+4\\-x&=6\\x&=-6\end{aligned}[/tex]

Therefore, for [tex]x<-4[/tex] the value of [tex]x[/tex] which satisfies the equation [tex]|x+4|=2[/tex] is [tex]x=-6[/tex].

This implies that the solution for the equation [tex]|x+4|=2[/tex] or the value of [tex]x[/tex] which satisfies the given equation are [tex]\fbox{\begin\\\ \math x=-2\ \text{and}\ x=-6\\\end{minispace}}[/tex].

Option 1:

The number line in option 1 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 1 is correct.

Option 2:

The number line in option 2 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=2[/tex] and [tex]x=4[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 2 is incorrect.

Option 3:

The number line in option 3 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=2[/tex] and [tex]x=6[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 3 is incorrect.

Option 4:

The number line in option 4 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-4[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 4 is incorrect.

Therefore, the number line for [tex]\fbox{\begin\\\ \bf \text{option 1}\\\end{minispace}}[/tex] represents the solution for the equation [tex]|x+4|=2[/tex].

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Functions

Keywords: Functions, modulus, modulus function, number line, real line, |x+4|=2, equation, root, zeroes, solutions,  absolute function, x=-6 and x=-2.

Option A is correct, the values of [tex]x[/tex] staisfying the given equation [tex]|x+4|=2[/tex] are [tex]-2[/tex] and [tex]-6[/tex].

Modulus function always returns a positive value to the equation.

Here, [tex]|x+4|[/tex] will give positive result if [tex]x>-4[/tex] and negative value if, [tex]x<-4[/tex].

Case 1: When [tex]x>-4[/tex]

According to the given equation,

[tex]|x+4|=2\\x=2-4\\x=-2[/tex]

So, the value of [tex]x[/tex] which satisfies the given equation [tex]|x+4|=2[/tex] for [tex]x>-4[/tex] is [tex]x=-2[/tex].

Case 2: When [tex]x<-4[/tex]

According to the given equation,

[tex]|x+4|=2\\-x-4=2\\x=-6[/tex]

So, the value of [tex]x[/tex] which satisfies the given equation [tex]|x+4|=2[/tex] for [tex]x<-4[/tex] is [tex]x=-6[/tex].

Hence, the values of [tex]x[/tex] staisfying the given equation [tex]|x+4|=2[/tex] are [tex]-2[/tex] and [tex]-6[/tex].

Now, according to the options, Option A is correct.

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