Answer:
[tex]y-1= \frac{4}{5} (x+2)[/tex]
Step-by-step explanation:
Using point-slope intercept form:
The equation of line is given by:
[tex]y-y_1 = m(x-x_1)[/tex] .....[1]
where,
m is the slope of the line and [tex](x_1, y_1)[/tex] is the point on the line.
As per the statement:
A line with slope 4/5 that contains the points (-2,1)
⇒m = [tex]\frac{4}{5}[/tex] and [tex](x_1, y_1)=(-2, 1)[/tex]
Substitute these values in [1] we have;
[tex]y-1= \frac{4}{5} (x+2)[/tex]
Therefore, [tex]y-1= \frac{4}{5} (x+2)[/tex] is the point slope form of a line with slope 4/5 that contains the points (-2,1).
