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two number that have a sum of 45 twice the greater number is six more than 5 times the lesser number

Respuesta :

the numbers will be X and Y with X being the lesser
x+y=45
2y=5x+6
now use a subtraction method to solve
x+y=45
y=45-x

2 (45-x)=5x+6
90-2x=5x+6
-7×=-84
x=12

y=45-12
y=33
so, x=12 and y=33

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